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Old 03-02-2009, 10:24 AM
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mes5107 mes5107 is offline
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Ok, using the 8.5 feet for a length yields approx 19.5 lengths. Does the Beyer figure system still use the charts which assign lengths and points behind according to distance? I've seen 9 furlong dirt races come home with a 14 second final quarter, and I've seen them come home in 12 seconds. Using just a chart based on distance does not give an accurate representation of lengths behind.
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Old 03-02-2009, 10:36 AM
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King Glorious King Glorious is offline
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I think that most people use .16 seconds per length now. At that rate. 3.35 seconds would equal 21 lengths.
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Old 03-02-2009, 12:24 PM
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Quote:
Originally Posted by King Glorious
I think that most people use .16 seconds per length now. At that rate. 3.35 seconds would equal 21 lengths.
.16 sec/length translates roughly to a 12 2/5 second final 1/8 of a mile. If all races finished at that speed, that would work just fine. However, a slower horse is going to take a longer amount of time to cover a length than a faster one and I think determining the distance of one horse behind another when only given the time interval is very dependent upon the final speeds of both horses in question.
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