pgardn-question

Ok I am a bit confused. It seems to me as light hits CdS (cadmium sulfide) that the resistance should decrease, not increase. The light should, by my reasoning, make for a looser electron configuration making current flow easier...

So the circuitry must involve a setup where if you cover the CdS photoresistor, the resistivity increases, so the current takes another pathway that allows current to flow from the battery to the LED. It must be that way. I could probably draw it out in a simple way.