![]() |
![]() |
![]() |
#6
|
||||
|
||||
![]() Quote:
I have 12 beaten lengths for the 3/4 CALL I have 3.5beaten lengths for the 1M CALL last 4 furlongs= =(660*(Q45-R45)+8*AE45)/(X45+0.18*BB45) =(660feet*(4furlongs)+8feet*12beaten lengths@call)/(51.04seconds+0.18*0beatenlengths@finish) =53.60502 feet per second 4furlongs or2640 feet/53.60502 feet per second = 49.24912281 seconds last 2 furlongs= =(660*(Q45-S45)+8*AF45)/(Y45+0.18*BB45) =(660feet*(2furlongs)+8feet*3.5beatenlengths@call)/(25.13seconds+0.18*0beatenlengths@finish) =53.64106645 feet per second 1320 feet/ 53.64106645 = 24.60801187 seconds last4furlong time 49.24912281 seconds minus last 2furlong time 24.60801187 seconds ------- = 24.64111094 seconds for 6f--->8f Last edited by Bobby Fischer : 05-06-2007 at 07:29 PM. |
Thread Tools | |
Display Modes | |
|
|