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Originally Posted by BillW
Basically you are adding:
D * 6.283 to the distance
where D = the distance the rail is out ( 12 or 18 feet in the case of the Mellon course)
so with the rail out 12 feet we add 75 feet to the race or 113 feet for the rail at 18 feet.
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Bill we spoke about this 2 years ago with CJ and the track super at Sar, remember?
Does your equation figure in for the whole trip, one turn turf, two turns? Is your equation for a circle...which a race track is NOT. The straight aways can't figure in to the added distance, ONLY the turns.
I'd love to drive a car or walk the course one day in the one path with the rails out at 12 feet and check the actual distance with a distance calibrator like road engeneers use. Then do the one path with rails out at 18 feet and so on.
Also, doesn't the distance out differ from inner and outer turf courses on your equation? The added distance HAS to be greater on the outer Belmont course than the inner with it's huge area and sweeping turns?